Question 77

Find the least number which should be subtracted from 9999 so that the difference is exactly divisible by 16?

Solution

$$\frac{9999}{16} = 624\frac{15}{16}$$

$$\frac{15}{16}\times 16 = 15$$

This 15 is needed to be subtracted from 9999 to get a number which is exactly divisible by 16

Option A is correct.

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