The area (in square units) of the region enclosed by the ellipse $$x^2 + 3y^2 = 18$$ in the first quadrant below the line $$y = x$$ is

A

$$\sqrt{3}\pi - \frac{3}{4}$$

B

$$\sqrt{3}\pi + 1$$

C

$$\sqrt{3}\pi$$

D

$$\sqrt{3}\pi + \frac{3}{4}$$