Question 76

In an examination, A obtains 10 percent less than the minimum number of marks required for passing. B obtains 11$$\frac{1}{9}$$ percent less than A. C obtains 41$$\frac{3}{17}$$ percent less than the number of marks obtained by A and B together. Does C pass the exam or fail?

Solution

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Let passing marks in the exam = 90

Marks obtained by A = 90% of 90 = 81

Marks obtained by B = $$(100 - 11\frac{1}{9})$$% of 81 = 72

Marks obtained by A and B together = 81 + 72 = 153

Marks obtained by C = $$(100 - 41\frac{3}{17})$$% of 153= 90

Hence, C will pass the exam

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