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Question 76
In an examination, A obtains 10 percent less than the minimum number of marks required for passing. B obtains 11$$\frac{1}{9}$$ percent less than A. C obtains 41$$\frac{3}{17}$$ percent less than the number of marks obtained by A and B together. Does C pass the exam or fail?
Solution
Let passing marks in the exam = 90
Marks obtained by A = 90% of 90 = 81
Marks obtained by B = $$(100 - 11\frac{1}{9})$$% of 81 = 72
Marks obtained by A and B together = 81 + 72 = 153
Marks obtained by C = $$(100 - 41\frac{3}{17})$$% of 153= 90
Hence, C will pass the exam
