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Instructions
In the following questions two equations numbered I and
II are given. You have to solve both the equations and
a: if x > y
b: if x ≥ y
c: if x < y
d: if x ≤ y
e: if x = y or the relationship cannot be established.
Solution
$$8x^2+18x+9 = 0$$
$$(4x+3)(2x+3) = 0$$
$$x = -\frac{3}{2}, -\frac{3}{4}$$
$$4y^2+19y+21 = 0$$
$$(4y+7)(y+3) = 0$$
$$y = -3, -\frac{7}{4}$$
x > y
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