Question 74

The sum of three numbers is 100. The ratio of the first number to the second number is 4 : 9 and the ratio of the second to the third number is 3 : 4. Find the second number.

Solution

let the first no be A, second no  be B and third no. C 

$$\frac{A}{B} = \frac{4}{9}$$

$$\frac{B}{C} = \frac{3}{4}$$

B is common in both so we have  to balance the B

$$\frac{A}{B} = \frac{4\times 3}{9\times 3}$$

$$\frac{B}{C} = \frac{3\times 9}{4\times 9}$$

$$\frac{A}{B} = \frac{12}{27}$$

$$\frac{B}{C} = \frac{27}{36}$$

so

12x + 27x + 36x = 100

75x = 100

x = $$\frac{4}{3}$$

so,second no = 27x = 36


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