Let $$[t]$$ denote the greatest integer less than or equal to $$t$$. Then the value of the integral $$\int_0^1 [-8x^2 + 6x - 1] dx$$ is equal to

A

$$-1$$

B

$$-\frac{5}{4}$$

C

$$\frac{\sqrt{17}-13}{8}$$

D

$$\frac{\sqrt{17}-16}{8}$$