Question 71
A natural number, when divided by 5, 6, 7 or 8, leaves a remainder of 4 in each case.What is the smallest of all such numbers?
Solution
LCM of the given three numbers is 840.
So the least number to leave a remainder of 4 when divided by 5, 6, 7 or 8 is 840 + 4 = 844
Hence, option C is the correct answer.
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