Question 70

Given,
(A) $$n = 5, m_{1} = -1$$
(B) $$n = 3, 1 = 2, m_{1} = -1, m_{2} = +\frac{1}{2}$$
The maximum number of electron(s) in an atom that can have the quantum numbers as given in (A) and (B) respectively are:

(A) n=5, ml=-1: possible in l=1,2,3,4 with ml=-1. Each has 2 electrons: total = 8.

(B) n=3, l=2, ml=-1, ms=+1/2: exactly 1 electron.

The answer is Option 2: 8 and 1.

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Given, (A) $$n = 5, m_{1} = -1$$ (B) $$n = 3, 1 = 2, m_{1} = -1, m_{2} = +\frac{1}{2}$$The maximum number of electron(s) in an atom that can have the quantum numbers as given in (A) and (B) respectively are: