Thirty men can do a piece of work in 16 days working 8 hrs a day. How many men are needed to complete another work, which is twice the first one, in 10 days working 12 hrs a day?
The following are the steps involved in solving the above problem. Arrange them in sequential order.

A) $$M_2 = \frac{30 \times 16 \times 8 \times 2x}{x \times 12 \times 10}$$

B) $$\frac{30 \times 16 \times 8}{x} = \frac{M_2 \times 12 \times 10}{2x}$$

C) $$\frac{M_1D_1H_1}{W_1} = \frac{M_2D_2H_2}{W_2}$$

D) $$M_2 = 64$$