Question 65

The base of a triangle is one-third of the base of a parallelogram having the same area as that of the triangle. The ratio of the corresponding heights of the triangle to the parallelogram will be:

Solution

The correct option is D.

Let the base of parallelogram is $$3x$$. So base of triangle is $$x$$.

Let height of triangle is $$h_{1}$$ and height of parallelogram is $$h_{2}$$.

Given that, Area of triangle = Area of parallelogram

$$\frac{1}{2}\times(x)\times(h_{1})=(3x)\times(h_{2})$$

$$\Rightarrow$$ $$h_{1}:h_{2}$$ = 6 : 1

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