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Let $$n^{th}$$ letter for $$14 \leq n \leq 26$$ in the English alphabet be coded as $$(n - 13)^{th}$$ letter and $$n^{th}$$ letter for $$1 \leq n \leq 13$$ be coded as $$(n + 13)^{th}$$ letter. For this coding pattern answer the question.
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