Question 64

The milk and water in two vessels A and B are in the ratio 4 : 3 and 2 : 3 respectively. In what ratio the liquids in both the vessels be mixed to obtain a new mixture in vessel C consisting half milk and half water?

Solution

Let mixture in vessel A = $$x$$ ml

and mixture in vessel B = $$y$$ ml

=> Milk in vessel A = $$\frac{4x}{7}$$

Milk in vessel B = $$\frac{2y}{5}$$

Acc to ques,

=> $$\frac{4x}{7} + \frac{2y}{5} = \frac{1}{2} (x + y)$$

=> $$\frac{4x}{7} - \frac{x}{2} = \frac{y}{2} - \frac{2y}{5}$$

=> $$\frac{x}{14} = \frac{y}{10}$$

=> $$\frac{x}{y} = \frac{14}{10} = \frac{7}{5}$$

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