Consider the parabola $$y^2 = 8x$$. Let $$\triangle _1$$ be the area of the triangle formed by the end points of its latus rectum and the point $$P\left(\frac{1}{2}, 2\right)$$ on the parabola, and $$\triangle_2$$ be the area of the triangle formed by drawing tangents at P and at the end points of the latus rectum. Then $$\frac{\triangle_1}{\triangle_2}$$ is