A hydrocarbon 'P' $$(C_{4}H_{8})$$ on reaction with HCl gives an optically active compound 'Cl' $$(C_{4}H_{9}Cl)$$ which on reaction with one mole of ammonia gives compound 'R' $$(C_{4}H_{11}N)$$ on diazolization followed by hydrolysis gives 'S'. Identify P, Q, Rand S.

A

B

C

D