Question 63

The present age of a father is equal to the sum of his son’s and wife’s present ages. The respective ratio between the present ages of his wife and son is 8 : 1 and the difference between his wife’s and son’s present ages is 28 years, what will be father’s age after 4 years ? (in years)

Solution

Let present age of wife = $$8x$$ years

=> Present age of son = $$x$$ years

Acc to ques,

=> $$8x - x = 28$$

=> $$x = \frac{28}{7} = 4$$

=> Present age of father = $$8x + x = 9x$$

= $$9 \times 4 = 36$$ years

$$\therefore$$ Father's age after 4 years = $$36 + 4 = 40$$ years

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