Team 'A' consists of 7 boys and $$n$$ girls and Team 'B' has 4 boys and 6 girls. If a total of 52 single matches can be arranged between these two teams when a boy plays against a boy and a girl plays against a girl, then $$n$$ is equal to:

Team A has 7 boys and $$n$$ girls. Team B has 4 boys and 6 girls. A single match is played between one player from Team A and one from Team B, with boys playing against boys and girls playing against girls.

The number of boy-vs-boy matches is $$7 \times 4 = 28$$.

The number of girl-vs-girl matches is $$n \times 6 = 6n$$.

Total matches = $$28 + 6n = 52$$.

Solving: $$6n = 52 - 28 = 24$$, so $$n = 4$$.

This matches Option C: $$n = 4$$.