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Solution of $$(D^2 + 4)y = \sin^2 x$$, is
$$y = A \cos 2x + B \sin 2x - \frac{1}{8} - \frac{x}{8} \sin 2x$$
$$y = A \cos 2x + B \sin 2x + \frac{1}{8} + \frac{x}{8} \sin 2x$$
$$y = A \cos 2x + B \sin 2x - \frac{1}{8} + \frac{x}{8} \sin 2x$$
$$y = A \cos 2x + B \sin 2x + \frac{1}{8} - \frac{x}{8} \sin 2x$$
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Quant Based DI
Routes And Networks
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Arrangement
Quant Based LR
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Data Interpretation Basics
Games and Tournamnents
Table with Missing values
2D & 3D LR
Selection With Condition
Venn Diagrams
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Truth Lie Concept
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Data change over a period
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