Match List - I with List - Il according to shape.
        List - I                      List - II
A. $$ XeO_3 $$                   I.     $$ BrF_5 $$
B. $$ XeF_2 $$                    II.    $$ NH_3 $$
C. $$ XeO_2 F_2 $$              III.   $$ [I_3]^-{} $$
D. $$ XeOF_4 $$                IV.   $$ SF_4 $$
Choose the correct answer from the options given below:

Use VSEPR theory to determine shapes and match them.

In the case of $$XeO_3$$, xenon has 8 valence electrons; forming three double bonds with oxygen uses 6 electrons and leaves one lone pair. The electron pair arrangement is tetrahedral, giving a trigonal pyramidal shape like $$NH_3$$, so it matches II (NH₃).

For $$XeF_2$$, xenon again has 8 valence electrons; bonding to two fluorines uses 2 electrons in bond pairs and leaves three lone pairs. The trigonal bipyramidal electron pair arrangement yields a linear shape like $$[I_3]^-$$, matching III ([I₃]⁻).

In $$XeO_2F_2$$, xenon forms two double bonds with oxygen and two single bonds with fluorine, leaving one lone pair. The trigonal bipyramidal electron pair arrangement produces a see-saw shape like $$SF_4$$, matching IV (SF₄).

With $$XeOF_4$$, xenon makes one double bond with oxygen and four single bonds with fluorine, leaving one lone pair. The octahedral electron pair arrangement leads to a square pyramidal shape like $$BrF_5$$, matching I (BrF₅).

Therefore the final matching is A-II, B-III, C-IV, D-I, which corresponds to Option 2.