Question 60

When one­ sixth of a number x, is added to 117, it becomes equal to y². If one ­fifth of y is equal to 2.2, what is the value of x ?

Solution

Given : $$\frac{1}{5} \times y = 2.2$$

=> $$y = 2.2 \times 5 = 11$$

Acc to ques,

=> $$(\frac{1}{6} \times x) + 117 = (y)^2$$

=> $$\frac{x}{6} + 117 = (11)^2 = 121$$

=> $$\frac{x}{6} = 121 - 117 = 4$$

=> $$x = 4 \times 6 = 24$$


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