The pressure difference between the inside and outside of a liquid droplet of diameter 'd' due to surface tension ($$\sigma$$) is given by the relation

A

$$\triangle P = \frac{4 \sigma}{d}$$

B

$$\triangle P = \frac{8 \sigma}{d}$$

C

$$\triangle P = \frac{2 \sigma}{d}$$

D

$$\triangle P = \frac{6 \sigma}{d}$$