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The pressure difference between the inside and outside of a liquid droplet of diameter 'd' due to surface tension ($$\sigma$$) is given by the relation
$$\triangle P = \frac{4 \sigma}{d}$$
$$\triangle P = \frac{8 \sigma}{d}$$
$$\triangle P = \frac{2 \sigma}{d}$$
$$\triangle P = \frac{6 \sigma}{d}$$
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