Question 6

The sum of digits of a two-digit number is 12. When the digits are interchanged, the resulting number is 36 more than the original number. What is the original two-digit number ?

Solution

Let the original number = $$10x + y$$

=> $$x + y = 12$$

On interchanging the digits, the number = $$10y + x$$

=> $$(10y + x) - (10x + y) = 36$$

=> $$9y - 9x = 36$$

=> $$y - x = 4$$

On solving above equations, we get :

=> $$x = 4$$ and $$y = 8$$

$$\therefore$$ Original number = 48

Create a FREE account and get: