Question 6

A rocket is launched normal to the surface of the Earth, away from the Sun, along the line joining the Sun and the Earth. The Sun is $$3\times10^{5}$$ times heavier than the Earth and is at a distance $$2.5\times10^{4}$$ times larger than the radius of the Earth. The escape velocity from Earth’s gravitational field is
$$\nu_{e}=11.2 kms^{-1}$$. The minimum initial velocity $$\nu_{s}$$ required for the rocket to be able to leave the Sun-Earth system is closest to

(Ignore the rotation and revolution of the Earth and the presence of any other planet)


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