If the average number of qualified candidates in 2006 and 2008 was 249, what per cent of appeared candidates qualified in the competitive exam in 2006 ?

Solution

Total no. of candidates qualified in 2006 & 2008 = 249*2 = 498

No. of candidates qualified in 2008 = $$\frac{60}{100}$$*480 = 288

No. of candidates qualified in 2006 = 498-288 = 210

% of candidates qualified in 2006 = $$\frac{210}{700}$$*100 = 30%

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