Please enter the following details
Free Daily Targets & Mocks
Study Material & Formulas PDFs
1 on 1 Mentorship
Question 57
The average of four consecutive numbers A, B, C and D respectively is 49.5. What is the product of B and D?
Solution
Since the ages of A, B, C, D are consecutive
Let the ages of A, B, C, D be n, n+1,n+2,n+3
$$\frac{n+n+1+n+2+n+3}{4} = 49.5$$
4n+6 = 49.5*4 = 198
4n = 192
n = 48
Ages of A, B, C, D = 48, 49, 50 ,51
Product of ages of B and D = 49*51 = (50-1)(50+1) =$$50^2-1$$ = 2500-1 = 2449.
Create a FREE account and get:
- Banking Quant Shortcuts PDF
- Free Banking Study Material - (15000 Questions)
- 135+ Banking previous papers with solutions PDF
- 100+ Online Tests for Free
