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Question 57

Solution of $$12$$ g of non-electrolyte (A) prepared by dissolving it in $$1000$$ mL of water exerts the same osmotic pressure as that of $$0.05$$ M glucose solution at the same temperature. The empirical formula of A is CH$$_2$$O. The molecular mass of A is _____ g. (Nearest integer)


Correct Answer: 240

We are given 12 g of non-electrolyte A dissolved in 1000 mL of water, exerting the same osmotic pressure as 0.05 M glucose at the same temperature. The empirical formula of A is CH$$_2$$O.

For non-electrolytes at the same temperature: $$\pi = CRT$$.

Since both solutions have the same osmotic pressure:

$$C_A = C_{\text{glucose}} = 0.05 \text{ M}$$

Volume of solution $$\approx 1000 \text{ mL} = 1 \text{ L}$$ (dilute solution).

$$n_A = 0.05 \times 1 = 0.05 \text{ mol}$$ $$M_A = \frac{\text{mass}}{n_A} = \frac{12}{0.05} = 240 \text{ g/mol}$$

Empirical formula mass of CH$$_2$$O = $$12 + 2 + 16 = 30$$ g/mol.

$$\frac{M_A}{\text{EFM}} = \frac{240}{30} = 8$$

Molecular formula = C$$_8$$H$$_{16}$$O$$_8$$.

The molecular mass of A is $$240$$ g.

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