Total number of candidates who appeared for CS and ES together in 2011 was 25% more than the total number of candidates who appeared for the same together in 2010. How many female candidates appeared for both the exams together in 2011 if they formed 2/5th of the total number of candidates appearing for both CS and ES exam that year ?

Total number of candidates appeared for CS and ES Exam in 2010 =$$ 76,000 + 40,000 = 1,16,000$$
Total number of candidates appeared for CS and ES Exam in 2011 = 1.25 $$ \times$$ Total number of candidates appeared for CS and ES Exam in 2010
= $$ 1.25 \times1,16,000 = \frac{5 \times 1,16,000}{4}$$
Total number of female candidates appeared for CS and ES Exam in 2011 = (2/5)th of Total number of candidates appeared for CS and ES Exam in 2011
= $$\frac{2}{5} \times \frac{5 \times 1,16,000}{4}$$
=$$ \frac{1,16,000}{2} = 58,000$$
Option B is the correct answer.