The final product [B] is :

Given compound: Cyclohexyl-CH₂-NH₂ (a primary amine)

Step 1: Reaction with C₆H₅COCl / NaOH

This is Schotten-Baumann Reaction (Acylation of amines)

What happens:

• Primary amine reacts with benzoyl chloride (C₆H₅COCl = PhCOCl)
• Forms an amide

Product [A]:

Cyclohexyl-CH₂-NHCOPh
(N-benzoyl derivative / amide)

Step 2: Reaction with LiAlH₄ / H₂O

This is Reduction of amides using LiAlH₄

What happens:

• Amides are reduced to amines
• The -CO- group is converted to -CH₂-

So:
-NHCOC₆H₅ → -NHCH₂C₆H₅

Final Product [B]:

Cyclohexyl-CH₂-CH₂-NH-CH₂-Ph

(This is a secondary amine)

Overall Reaction Summary:

1. Amine → Amide
2. Amide → Secondary amine

Final Answer:

B = Cyclohexyl-CH₂-NH-CH₂-Ph