Jar A has ‘x’ ml mixture of milk and water, of which 40% is water. Jar B also has mixture of milk and water, of which 20% is water. The quantity of mixture in Jar B is twice that of Jar A. If the content of Jar B is emptied into Jar A completely and the resultant quantity of milk in Jar A is 198 ml, what is the value of ‘x’ ?

Total quantity of mixture in jar A = $$x$$ ml

% of milk in jar A = 100 - 40 = 60%

Quantity of milk in jar A = $$\frac{60}{100} \times x = \frac{3 x}{5}$$ ml

Total quantity of mixture in jar B = $$2x$$ ml

% of milk in jar B = 100 - 20 = 80%

Quantity of milk in jar B = $$\frac{80}{100} \times 2x = \frac{8 x}{5}$$ ml

=> Total quantity of milk in jar A and B = $$\frac{3 x}{5} + \frac{8 x}{5} = 198$$

=> $$\frac{11 x}{5} = 198$$

=> $$x = 198 \times \frac{5}{11} = 18 \times 5$$

=> $$x = 90$$ ml