In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate option.
Give answer :
a: If x > y
b: If x < y
c: If x ≥ y
d: If x ≤ y
e: If x = y or the relationship cannot be established
I.$$8x^{2} + 25x + 3 =0$$
II. $$2y^{2} + 17y + 30 = 0$$
Root of quadratic equation $$(ax^{2} + bx + c =0)$$ = $$\frac{-b \pm \sqrt{b^2 -4ac}}{2a}$$
For equation I : a=8 , b = 25 and c= 3
On solving the quadratic equation I we get x = (-3) or (-2/16)
For equation II : a=2 , b = -17 and c= 30
On solving the quadratic equation I we get y = (-6) or (-10/4)
As we can see, no relationship can be established between x and y.
Therefore, option E is the correct answer.
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