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One of the roots of the equation $$x^2 - 6x + k = 0$$ is $$x = 2$$. The other root is:
The correct option is B.
Let f($$x$$) = $$x^2 - 6x + k = 0$$ if $$x$$ = 2 is a root then f(2)=0
$$\Rightarrow$$ $$2^2 - 6\times2+ k=0$$
$$\Rightarrow$$ k = 8
Now f(x) = $$x^2 - 6x + 8= 0$$
Now check from option x =4 satisfied. So other root is x = 4
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