Given below are two statements :
Statement I : The number of compounds among SO$$_2$$, SO$$_3$$, SF$$_4$$, SF$$_6$$ and H$$_2$$S in which sulphur does not obey the Octet rule is 3.
Statement II : Among [H$$_2$$O, ClF$$_3$$, SF$$_4$$], [NH$$_3$$, BrF$$_5$$, SF$$_4$$], [BrF$$_5$$, ClF$$_3$$, XeF$$_4$$] and [XeF$$_4$$, ClF$$_3$$, H$$_2$$O], the number of sets in which all the molecules have one lone pair of electrons on the central atom is 1.
In the light of the above statements, choose the correct answer from the options given below :

In the molecules (SO_2), (SO_3), (SF_4), (SF_6), and (H_2S), the number of electrons around the sulphur atom is as follows:

• (SO_2): Sulphur has an expanded octet with (10) electrons.
• (SO_3): Sulphur has an expanded octet with (12) electrons.
• (SF_4): Sulphur has an expanded octet with (10) electrons.
• (SF_6): Sulphur has an expanded octet with (12) electrons.
• (H_2S): Sulphur has (8) electrons and obeys the octet rule.

Thus, sulphur does not obey the octet rule in 4 compounds, namely (SO_2), (SO_3), (SF_4), and (SF_6).

Therefore, Statement I is false.

Now consider the number of lone pairs on the central atom:

• (H_2O): (2) lone pairs
• (ClF_3): (2) lone pairs
• (SF_4): (1) lone pair
• (NH_3): (1) lone pair
• (BrF_5): (1) lone pair
• (XeF_4): (2) lone pairs

Checking the given sets:

• ([H_2O,\ ClF_3,\ SF_4]): (2,\ 2,\ 1) lone pairs
• ([NH_3,\ BrF_5,\ SF_4]): (1,\ 1,\ 1) lone pair
• ([BrF_5,\ ClF_3,\ XeF_4]): (1,\ 2,\ 2) lone pairs
• ([XeF_4,\ ClF_3,\ H_2O]): (2,\ 2,\ 2) lone pairs

Only the second set contains molecules in which the central atom has exactly one lone pair.

Therefore, Statement II is true.

Hence, Statement I is false and Statement II is true.