Which of the following represents the correct trend for the mentioned property ?
A.$$F > P > S > B$$  - First Ionization Energy
B.$$Cl > F > S > P$$ - Electron Affinity
C. $$K > Al > Mg > B$$ - Metallic character
D. $$K_{2}O > Na_{2}O > MgO > AL_{2}O_{3}$$ - Basic character
Choose the correct answer from the options given below :

(A) First Ionization Energy

First ionization energy is the energy required to remove the outermost electron from an isolated gaseous atom.

General trend:

• Increases across a period (left to right)
• Decreases down a group

Exception:
P has higher ionization energy than S due to half-filled stability (P: $$3p³$$, S: $$3p⁴$$ has electron-electron repulsion).

Correct order:
F > P > S > B

Hence, option (A) is correct.

(B) Electron Affinity

Electron affinity is the energy released when an electron is added to an isolated gaseous atom.

General trend:

• Increases across a period
• Decreases down a group

Exception:
Cl has higher electron affinity than F due to lower electron-electron repulsion in the larger size of Cl.

Correct order:
Cl > F > S > P

Hence, option (B) is correct.

(C) Metallic Character

Metallic character is the tendency of an element to lose electrons.

General trend:

• Decreases across a period
• Increases down a group

Correct order should be:
K > Mg > Al > B

Given order (K > Al > Mg > B) is incorrect.

Hence, option (C) is incorrect.

(D) Basic Character of Oxides

Basic character is the tendency of oxides to react with acids.

General trend:

• Increases with metallic character

Correct order:
$$K₂O > Na₂O > MgO > Al₂O₃$$

($$Al₂O₃$$ is amphoteric)

Hence, option (D) is correct.

Final answer: A, B and D are correct