1.86 g of aniline completely reacts to form acetanilide. 10% of the product is lost during purification. Amount of acetanilide obtained after purification (in g) is ______ $$\times 10^{-2}$$.

Aniline reacts with acetic anhydride (or acetyl chloride) to form acetanilide in an acetylation reaction:

$$C_6H_5NH_2 + CH_3COCl \rightarrow C_6H_5NHCOCH_3 + HCl$$

The molar mass of aniline ($$C_6H_5NH_2$$) is $$93$$ g/mol, and the molar mass of acetanilide ($$C_6H_5NHCOCH_3$$) is $$135$$ g/mol.

Moles of aniline = $$\frac{1.86}{93} = 0.02$$ mol.

Since 1 mole of aniline produces 1 mole of acetanilide, the theoretical yield of acetanilide = $$0.02 \times 135 = 2.70$$ g.

However, 10% of the product is lost during purification. So the actual amount obtained = $$2.70 \times 0.9 = 2.43$$ g = $$243 \times 10^{-2}$$ g.

The value of the answer is $$\textbf{243}$$.