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Question 51

The number of species having a square planar shape from the following is
XeF$$_4$$, SF$$_4$$, SiF$$_4$$, BF$$_4^-$$, BrF$$_4^-$$, [Cu(NH$$_3$$)$$_4$$]$$^{2+}$$, [FeCl$$_4$$]$$^{2-}$$, [PtCl$$_4$$]$$^{2-}$$


Correct Answer: 4

We need to count the number of species with square planar geometry from the given list.

1. XeF$$_4$$: Xe has 4 bond pairs and 2 lone pairs (sp$$^3$$d$$^2$$). The geometry is square planar. ✔

2. SF$$_4$$: S has 4 bond pairs and 1 lone pair (sp$$^3$$d). The geometry is see-saw (trigonal bipyramidal with one equatorial lone pair). ✘

3. SiF$$_4$$: Si has 4 bond pairs and 0 lone pairs (sp$$^3$$). The geometry is tetrahedral. ✘

4. BF$$_4^-$$: B has 4 bond pairs and 0 lone pairs (sp$$^3$$). The geometry is tetrahedral. ✘

5. BrF$$_4^-$$: Br has 4 bond pairs and 2 lone pairs (sp$$^3$$d$$^2$$). The geometry is square planar. ✔

6. [Cu(NH$$_3$$)$$_4$$]$$^{2+}$$: Cu$$^{2+}$$ is a d$$^9$$ ion. With NH$$_3$$ as a strong field ligand, it adopts a square planar geometry (due to Jahn-Teller distortion). ✔

7. [FeCl$$_4$$]$$^{2-}$$: Fe$$^{2+}$$ is d$$^6$$ with Cl$$^-$$ (weak field). This is a tetrahedral complex. ✘

8. [PtCl$$_4$$]$$^{2-}$$: Pt$$^{2+}$$ is a d$$^8$$ ion. All d$$^8$$ complexes of heavy transition metals are square planar. ✔

Count: XeF$$_4$$, BrF$$_4^-$$, [Cu(NH$$_3$$)$$_4$$]$$^{2+}$$, [PtCl$$_4$$]$$^{2-}$$ = 4 species.

The correct answer is 4.

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