The number of bent-shaped molecule/s from the following is _______ N$$_3^-$$, NO$$_2$$, I$$_3^-$$, O$$_3$$, SO$$_2$$

Find the number of bent-shaped molecules from: N$$_3^-$$, NO$$_2$$, I$$_3^-$$, O$$_3$$, SO$$_2$$.

N$$_3^-$$ (Azide ion): Central N has 2 bond pairs, 0 lone pairs. Geometry: linear. Not bent.

NO$$_2$$ (Nitrogen dioxide): Central N has 2 bond pairs + 1 unpaired electron. Geometry: bent (bond angle ~134°). $$\checkmark$$

I$$_3^-$$ (Triiodide ion): Central I has 2 bond pairs + 3 lone pairs. Geometry: linear. Not bent.

O$$_3$$ (Ozone): Central O has 2 bond pairs + 1 lone pair. Geometry: bent (bond angle ~117°). $$\checkmark$$

SO$$_2$$ (Sulfur dioxide): Central S has 2 bond pairs + 1 lone pair. Geometry: bent (bond angle ~119°). $$\checkmark$$

Bent-shaped molecules: NO$$_2$$, O$$_3$$, SO$$_2$$ = 3 molecules.

The correct answer is 3.