The energy of one mole of photons of radiation of frequency $$2 \times 10^{12}$$ Hz in J mol$$^{-1}$$ is ______ . (Nearest integer)
(Given: h $$= 6.626 \times 10^{-34}$$ Js, N$$_A = 6.022 \times 10^{23}$$ mol$$^{-1}$$)

We need to find the energy of one mole of photons of radiation with frequency $$2 \times 10^{12}$$ Hz.

Formula: $$E = N_A h\nu$$

Calculation:

$$E = 6.022 \times 10^{23} \times 6.626 \times 10^{-34} \times 2 \times 10^{12}$$

$$= 6.022 \times 6.626 \times 2 \times 10^{23-34+12}$$

$$= 6.022 \times 13.252 \times 10^{1}$$

$$= 79.80 \times 10^{1}$$

$$\approx 798$$ J mol$$^{-1}$$

The energy is $$\boxed{798}$$ J mol$$^{-1}$$.