Number of moles and number of molecules in 1.4187 L of $$\text{SO}_2$$ at STP respectively are :

At STP ($$273 K$$ and $$1 atm$$) one mole of any ideal gas occupies $$22.4$$L.

Number of moles of $$SO_2$$ present is given by the relation 

$$n = \frac{V}{V_m} = \frac{1.4187\; \text{L}}{22.4\; \text{L mol}^{-1}}$$

Carrying out the division, $$n = 0.0633\; \text{mol}$$ (rounded to four significant figures).

The number of molecules $$N$$ is obtained by multiplying the moles by Avogadro’s number ($$N_A$$)

$$N_A = 6.022 \times 10^{23}\; \text{mol}^{-1}$$: $$N = n N_A = 0.0633 \times 6.022 \times 10^{23}$$

$$N = 3.812 \times 10^{22}\; \text{molecules}$$

Thus, the sample contains $$0.0633$$ moles and $$3.812 \times 10^{22}$$ molecules of $$SO_2$$ respectively.

Option B which is: $$0.0633;\; 3.812 \times 10^{22}$$