An organic compound gives $$0.220$$ g of CO$$_2$$ and $$0.126$$ g of H$$_2$$O on complete combustion. If the % of carbon is $$24$$ then the % of hydrogen is _____ $$\times 10^{-1}$$. (Nearest integer)

An organic compound gives 0.220 g of CO$$_2$$ and 0.126 g of H$$_2$$O on complete combustion, and the percentage of carbon is 24%.

$$\text{Mass of C} = \frac{12}{44} \times 0.220 = \frac{12 \times 0.220}{44} = \frac{2.64}{44} = 0.06 \text{ g}$$

$$\text{Mass of H} = \frac{2}{18} \times 0.126 = \frac{0.252}{18} = 0.014 \text{ g}$$

Since the percentage of carbon is 24%:

$$\frac{0.06}{m} \times 100 = 24$$

$$m = \frac{0.06 \times 100}{24} = 0.25 \text{ g}$$

$$\% \text{H} = \frac{0.014}{0.25} \times 100 = 5.6\%$$

The percentage of hydrogen is $$5.6 = 56 \times 10^{-1}$$.

The answer is $$\mathbf{56}$$.