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A satellite of mass 1000 kg is launched to revolve around the earth in an orbit at a height of 270 km from the earth's surface. Kinetic energy of the satellite in this orbit is _________ $$\times 10^{10}$$ J.
(Mass of earth = $$6 \times 10^{24}$$ kg, Radius of earth = $$6.4 \times 10^6$$ m, Gravitational constant = $$6.67 \times 10^{-11}$$ Nm$$^2$$ kg$$^{-2}$$)
Correct Answer: 3
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