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RRB ALP 30th Aug 2018 Shift-2 Question 5

Question 5

A steel rod of length $$ 20 \frac{3}{26} $$ is cut out from a rod of length $$ 56 \frac{1}{5} $$. What then is the remaining length of the rod?

Solution

The remaining length of the rod = $$\frac{281}{5} - \frac{523}{26} = \frac{7306 - 2615}{26 \times 5} = \frac{4691}{130} =36\frac{11}{130}$$

So , the answer would be option d)$$36\frac{11}{130}$$



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