Question 5

A steel rod of length $$ 20 \frac{3}{26} $$ is cut out from a rod of length $$ 56 \frac{1}{5} $$. What then is the remaining length of the rod?

Solution

The remaining length of the rod = $$\frac{281}{5} - \frac{523}{26} = \frac{7306 - 2615}{26 \times 5} = \frac{4691}{130} =36\frac{11}{130}$$

So , the answer would be option d)$$36\frac{11}{130}$$

Create a FREE account and get:

Download RRB Study Material PDF
45+ RRB previous papers with solutions PDF
300+ Online RRB Tests for Free

CAT Quant Questions | CAT Quantitative Ability

CAT Venn Diagrams Questions CAT Simple Interest Compound Interest Questions CAT Remainders Questions CAT Linear Equations Questions CAT Coordinate Geometry Questions

CAT DILR Questions | LRDI Questions For CAT

CAT Truth Lie Concept Questions CAT Quant Based LR Questions CAT Quant Based DI Questions CAT Charts Questions CAT Scheduling Questions

CAT Verbal Ability Questions | VARC Questions For CAT

CAT Para Jumbles Questions CAT Reading Comprehension Questions CAT Verbal Ability Questions CAT Odd One Out Questions CAT Critical Reasoning Questions

Follow us on

Boost your Prep!

Download App