18 men can complete a project in 30 days and 16 women can complete the same project in 36 days. 15 men start working and after 9 days they are replaced by 18 women. In how many days will 18 women complete the remaining work ?
$$\frac{M1D1}{W1}$$ = $$\frac{M2D2}{W2}$$
W1=W2 = Q
$$\frac{18Mx30}{Q}$$ = $$\frac{16Wx36}{Q}$$
M = $$\frac{32}{30}$$W ....(1)
Let the days required by 18 women to complete the remaining work = y days
so $$\frac{(15M\times9)+(18W \times y)}{Q}$$ = $$\frac{16W\times36}{Q}$$ ......(2)
using equation 1 and 2
$$\frac{(16W\times9)+(18W \times y)}{Q}$$ = $$\frac{16W\times36}{Q}$$
144W + 18Wy = 576W
18Wy = 432 W
y = 24 days
Create a FREE account and get:
