Match List I with List II.

List I (Monomer Unit)	List II (Polymer)
(a) Caprolactum	(i) Natural rubber
(b) 2-Chloro-1,3-butadiene	(ii) Buna-N
(c) Isoprene	(iii) Nylon 6
(d) Acrylonitrile	(iv) Neoprene

Choose the correct answer from the options given below:

We need to match each monomer with its corresponding polymer.

Caprolactam is the monomer of Nylon 6. Nylon 6 is formed by the ring-opening polymerisation of caprolactam. So $$(a) \to (iii)$$.

2-Chloro-1,3-butadiene (also called chloroprene) is the monomer of Neoprene. Neoprene is a synthetic rubber formed by the polymerisation of chloroprene. So $$(b) \to (iv)$$.

Isoprene (2-methyl-1,3-butadiene) is the monomer unit of natural rubber. Natural rubber is cis-1,4-polyisoprene. So $$(c) \to (i)$$.

Acrylonitrile is one of the monomers used in making Buna-N (also called nitrile rubber). Buna-N is a copolymer of 1,3-butadiene and acrylonitrile. So $$(d) \to (ii)$$.

The correct matching is: $$a \to iii$$, $$b \to iv$$, $$c \to i$$, $$d \to ii$$.

Hence, the correct answer is Option A.