The SI on certain sum of money for 15 months at rate of 7.5% per annum exceed the SI on same sum at 12.5% per annum for 8 months by Rs. 3,250/-, find the sum.
Let the principal = Rs. $$P$$
$$S.I. = \frac{P \times R \times T}{100}$$
Acc. to ques,
=> $$(\frac{P \times 7.5 \times 15}{100 \times 12}) - (\frac{P \times 12.5 \times 8}{100 \times 12}) = 3250$$
=> $$\frac{112.5P}{1200} - \frac{100P}{1200} = 3250$$
=> $$12.5P = 3250 \times 1200 = 3900000$$
=> $$P = \frac{3900000}{12.5} = 3,12,000$$
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