Suitable reaction condition for preparation of Methyl phenyl ether is

Methyl phenyl ether (anisole, PhOCH₃) is prepared by Williamson ether synthesis.

In Williamson synthesis, a phenoxide ion (or alkoxide) reacts with a primary alkyl halide via S_N2 mechanism.

The best combination is: sodium phenoxide (PhO⁻Na⁺) + methyl bromide (MeBr)

$$PhO^-Na^+ + CH_3Br \to PhOCH_3 + NaBr$$

Note: Option 3 (PhBr + MeO⁻Na⁺) would not work well because aryl halides do not undergo S_N2 reactions easily.

The correct answer is Option 4: PhO⁻Na⁺, MeBr.