Assume the population of Panchagarh in 2016 is 450000. Then the combined non-male population of cities P, Q and T is approximately what percent more/less than the combined male populations of cities R, S and T?

Given that the population of Panchagarh in 2016 was 450000.

Population of P = $$\ \ \ \ \ \dfrac{\ 20}{100}\times\ 450000\ =90000$$

Non male population of P = $$\ \ \ \ \ \dfrac{\ 80}{100}\times\ 90000\ =72000$$

Population of Q = $$\ \ \ \ \ \dfrac{\ 28}{100}\times\ 450000\ =126000$$

Non male population of Q = $$\ \ \ \ \ \dfrac{\ 35}{100}\times\ 126000\ =44100$$

Population of T = $$\ \ \ \ \ \dfrac{\ 12}{100}\times\ 450000\ =54000$$

Male population of T = $$\ \ \ \ \ \dfrac{\ 60}{100}\times\ 54000\ =32400$$

Non male population of T = $$\ \ \ \ \ \dfrac{\ 40}{100}\times\ 54000\ =21600$$

Population of R = $$\ \ \ \ \ \dfrac{\ 25}{100}\times\ 450000\ =112500$$

Male population of R = $$\ \ \ \ \ \dfrac{\ 45}{100}\times\ 112500\ =50625$$

Population of R = $$\ \ \ \ \ \dfrac{\ 25}{100}\times\ 450000\ =112500$$

Male population of R = $$\ \ \ \ \ \dfrac{\ 45}{100}\times\ 112500\ =50625$$

Population of S = $$\ \ \ \ \ \dfrac{\ 15}{100}\times\ 450000\ =67500$$

Male population of S = $$\ \ \ \ \ \dfrac{\ 50}{100}\times\ 67500\ =33750$$

Combined male population of R,S,T = 50625 + 33750 + 32400 = 116775

Combined non-male population of P, Q ,T = 72000 + 44100 + 21600 = 137700

Combined non male population of P,Q, T is higher than the combined male population of R, S,T by $$\ \ \ \ \ \dfrac{\ 137700-116775}{116775}=17.919\%\ \simeq\ 18\%\ \ $$