A thermodynamic system is taken through the cyclic process $$ABC$$ as shown in the figure. The total work done by the system during the cycle $$ABC$$ is ______ J.

In a cyclic process on a P-V diagram, net work done equals area enclosed by the loop.

From graph:

• $$A=(2m^3,100Pa)$$
• $$B=(5m^3,300Pa)$$
• $$C=(5m^3,100Pa)$$

The path ABCA forms a triangle.

Work done = area of triangle

$$W=\frac{1}{2}\times\text{base}\times\text{height}$$

Base (change in volume):

$$5-2=3\ \text{m}^3$$

Height (change in pressure):

$$300-100=200\ \text{Pa}$$

So,

$$W=\frac{1}{2}(3)(200)$$

$$W=300\ \text{J}$$