Jar A contains 78 litres of milk and water in the respective ratio of 6 : 7. 26 litres of the mixture was taken out from Jar A. What quantity of milk should be added to jarA, so that water constitutes 40% of the resultant mixture in jar A?

Jar A has 78 litres of mixture of milk and water in the respective ratio of 6 : 7

=> Quantity of milk in Jar A = $$\frac{6}{13} \times 78 = 36$$ litres

Quantity of water in Jar A = $$78 - 36 = 42$$ litres

26 litres of the mixture was taken out from Jar A, i.e., $$\frac{26}{78} = (\frac{1}{3})^{rd}$$

=> Milk left = $$36 - \frac{1}{3} \times 36 = 24$$

Water left = $$42 - \frac{1}{3} \times 42 = 28$$

Let milk added to jar A = $$x$$ litres

Acc. to ques, => $$\frac{24 + x}{28} = \frac{60}{40}$$

=> $$\frac{24 + x}{28} = \frac{3}{2}$$

=> $$48 + 2x = 84$$

=> $$2x = 84 - 48 = 36$$

=> $$x = \frac{36}{2} = 18$$ litres