The circumference of the semicircle is 180 cm. If the side of a square is 60% more than the diameter of the circle, What is the perimeter of the square ?
Given that circumference of semi circle is = 180
let the radius of this Semi circle be R
So, R = $$\frac{180\times7}{36}$$
Diameter of this semi circle (D) = 2R
Side of the square = 1.6 D = 1.6 x 2R
Perimeter of square = 4 x side = 4 x 3.2 x R = 448
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