In figure, a straight line is given for Freundrich Adsorption ($$y = 3x + 2.505$$). The value of $$\frac{1}{n}$$ and log K are respectively.

We are given the Freundlich adsorption isotherm plotted as a straight line: $$y = 3x + 2.505$$.

The Freundlich equation is: $$\frac{x}{m} = K \cdot p^{1/n}$$

Taking logarithm:

$$\log\frac{x}{m} = \log K + \frac{1}{n}\log p$$

Comparing with $$y = 3x + 2.505$$:

Here $$y = \log(x/m)$$ and $$x$$-axis = $$\log p$$.

Slope = $$\frac{1}{n} = 3$$

Intercept = $$\log K = 2.505$$

$$\frac{1}{n} = 3$$ and $$\log K = 2.505$$.

The correct answer is Option C: $$3$$ and $$2.505$$.