Sign in
Please select an account to continue using cracku.in
↓ →
What is the sum of the total surface areas of all the cubes formed when a cuboid of size 5.2m $$\times$$ 13m $$\times$$ 39m is cut completely into the least possible number of cubes, all of which arg identical?
HCF of sides of cuboid = 2.6
So, side of each cube = 2.6 m
Least number of cubes formed = $$\frac{5.2 * 13 * 39}{2.6 * 2.6 * 2.6} = 150$$
Total surface area of each = $$6 * 2.6^2 = 40.56 m^2$$
Sum of total surface area of all the cubes = 150 * 40.56 = 6084 $$m^2$$
Was this solution helpful?
Click on the Email ☝️ to Watch the Video Solution
Book Free CAT Mentorship
Get personalized CAT strategy from a 99%iler
500+ students mentored
OTP Verification
Enter the 6-digit code sent to your phone
Booking Summary
Enter OTP
Didn't receive the OTP?
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation